Wednesday, November 21, 2007

9009£3 |-|4x0r

9009£3 |-|4x0r 1$ |-|4X0R!! (£1(|{ |-|3r3 ƒ0r |\/|0r3 9009£3 |-|4(|{$! 1 µ$3Ð 7|-|3 £337 7r4|\|$£470r - 17 7r4|\|$£473$ normal text 70 $p3(14£ 73x7 £1|{3 7|-|1$. 7|-|1$ \/\/|-|0£3 b£0(|{ 0ƒ 73x7 |-|4$ 80% £337|\|3$$.

(Hope you can read that!)


1 comment:

victorkoo.jr. said...

Really hope you can read that. And reply.